Induced EMF: Solenoid in Square Loop

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SUMMARY

The discussion focuses on calculating the induced electromotive force (EMF) in a square loop of wire surrounding a solenoid with a time-varying current described by I(t) = I₀(1 - e^(-αt)). The key equation used is ε = -N(dφ/dt), where φ represents the magnetic flux. Participants emphasize the need to apply Ampere's circuital law to determine the magnetic field of the solenoid, which is essential for accurately calculating the electric flux and induced EMF. The integration of the magnetic field is crucial, as it is not constant, and the constants a and b are significant for the calculations.

PREREQUISITES
  • Understanding of electromagnetism principles, specifically Faraday's law of induction.
  • Familiarity with Ampere's circuital law for calculating magnetic fields.
  • Knowledge of calculus, particularly integration techniques.
  • Concept of magnetic flux and its relation to induced EMF.
NEXT STEPS
  • Study the derivation of the magnetic field inside a solenoid using Ampere's circuital law.
  • Learn about the relationship between magnetic flux and induced EMF in varying magnetic fields.
  • Explore advanced integration techniques relevant to electromagnetism problems.
  • Investigate the concept of inductance and its calculation in circuits involving solenoids.
USEFUL FOR

Students and educators in physics, particularly those studying electromagnetism, electrical engineering students, and anyone involved in solving problems related to induced EMF in circuits.

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Homework Statement



The solenoid has N turns of wire around a cylinder. The radius of the cylinder is "a" and length is "b." THe current of the solenoid varies as I(t)= I[tex]_{0}[/tex](1 - e^-[tex]\alpha[/tex]t) . I[tex]_{0}[/tex] and [tex]\alpha[/tex] are positive constants. Around the solenoid is a square loop of wire with side length "c." The axis of the square loop is parallel to and coincides with the axis of the solenoid. What is the magnitude of the induced EMF in the square loop?





Homework Equations



[tex]\epsilon[/tex] = -N[tex]\frac{d\phi}{dt}[/tex]




The Attempt at a Solution



[tex]\epsilon[/tex] = -N[tex]\frac{d\phi}{dt}[/tex]

d[tex]\epsilon[/tex] = -N[tex]\frac{dBA}{dt}[/tex]

[tex]\epsilon[/tex] = -NA[tex]\int[/tex]dB

[tex]\epsilon[/tex] = (-NA)[([tex]\mu[/tex]NI)/B]
 
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Thats not strictly correct. The magnetic field of the solenoid is not a constant which you can integrate as you did. You are given the constants a and b for a reason. You can find the magnetic field by using ampere's circuital law. That is what you must integrate.
 
Would I need to use the B-field of the solenoid to find the electric flux and then finally the inductance? I think I'm having a hard time grasping the concept of the question. I'm assuming the solenoid and cylinder are the same. Is that what you assume as well?
 
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