Inductance: Current in terms of Voltage

AI Thread Summary
To solve the problem of reducing the current in a 0.6H inductance from 8A to 0A in 0.4 seconds, the correct voltage applied should be -12V, not 12V or 10V as initially calculated. The equation used, i(t) = (1/L) ∫v(t) dt + i(t0), is appropriate, but the limits and voltage sign must be carefully considered. The negative voltage indicates that the applied voltage must oppose the current flow to achieve the desired result. Therefore, the book's answer of 10V is incorrect, confirming that the proper voltage is indeed -12V. Understanding the direction of current and voltage in inductive circuits is crucial for accurate calculations.
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I'm having a bit of trouble getting the right answer for a problem in my electrical engineering textbook. The question is:

At t=0, the current flowing in a 0.6H inductance is 8A. What constant voltage must be applied to reduce the current to 0A at t=0.4s.

I'm using the equation:

i(t)=\frac{1}{L}\int\ v(t).dt+i(t_{0}) with limits 0.4s and 0s

The answer I'm getting is 12V, and the book says 10V.. which is right??

I'm using L=0.6H, i(t0)=8A, and i(t)=0A

Please help!
 
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It seems the book answer is wrong. And so is yours. The correct answer would be -12V.
 
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