- #1
Faiq
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Homework Statement
The question is uploaded.
Value of g = ## \small \rm 10~ms^{-2}##
Inertia of the individual square lamina = ## \rm \small \frac{1}{12}mr^2 ~kgm^{2}##
The Attempt at a Solution
$$\ C=Ia$$
$$\ Moment~of~Weight~of~Particle=1.594a$$
$$\ 0.3*2g=1.594a$$
$$\ 6=1.594a$$
$$\ a=3.764$$
$$\ \omega^2 = 2a\theta$$
$$\ \omega^2 = 2*3.764*2*\pi$$
$$\ \omega^2 = 47.3$$
$$\ \omega = 6.88$$
However the answer given is ## \small \rm 6.52 ~rads^{-1}##
Can somebody please check my working and show me the flaw in my method?
There is also a method to solve this using energy consideration. Can somebody show me that method?
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