Inertia matrix of a homogeneous cylinder

AI Thread Summary
The discussion focuses on understanding the derivation of the inertia matrix for a homogeneous cylinder, specifically the terms (1/4)mR^2 + (1/12)ml^2 and (1/2)mR^2. Participants express confusion about how these terms are derived from integrals involving coordinates y' and z', which are not clearly defined. The importance of integrating these terms with respect to mass and understanding the variable density is emphasized. A suggestion is made to use the relationship between mass, density, and volume to clarify the derivation process. The conversation highlights the need for clearer definitions and step-by-step integration to resolve the confusion.
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Homework Statement


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Homework Equations


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The Attempt at a Solution


What I am confused about is where they got the (1/4)mR^2 + (1/12)ml^2 and (1/2)mR^2 from? I am guessing that these came from the integral of y'^2 + z'^2 and x'^2 +y'^2 but I don't understand how this happened exactly? Could someone point me in the right direction?

Thanks
 
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Did you try actually computing the integrals? What did youget? Please show your work.
 
Orodruin said:
Did you try actually computing the integrals? What did youget? Please show your work.

What are y'^2 and z'^2? I don't know what to sub in for these (not sure what they represent?) so can't do the integral until I know them.
 
They are coordinates as shown in the figure.
 
Orodruin said:
They are coordinates as shown in the figure.
I understand that but I mean how would one integrate those terms with respect to m? They aren't constants?
 
They depend on where in the body you are.
 
Orodruin said:
They depend on where in the body you are.
Sorry for the late reply. I am still confused. I just want to know how they (mathematically) got from the left hand side to the right. I don't understand how integrating the left hand side yields the right hand side.
 
Use ##dm = \rho \, dx'dy'## and integrate over ##x'## and ##y'## with the appropriate boundaries. The value of ##\rho## in terms of the total mass ##m## can be inferred by computing the volume ##V## of the body and using ##\rho V = m##.
 
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