Inertia matrix of a homogeneous cylinder

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SUMMARY

The discussion focuses on deriving the inertia matrix of a homogeneous cylinder, specifically the expressions (1/4)mR² + (1/12)ml² and (1/2)mR². Participants clarify that these expressions result from integrating the squared coordinates y'², z'², and x'², which represent the distribution of mass in the cylinder. The integration process involves using the differential mass element ##dm = \rho \, dx'dy'## and applying the appropriate boundaries to compute the total mass from the volume of the cylinder.

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Homework Statement


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Homework Equations


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The Attempt at a Solution


What I am confused about is where they got the (1/4)mR^2 + (1/12)ml^2 and (1/2)mR^2 from? I am guessing that these came from the integral of y'^2 + z'^2 and x'^2 +y'^2 but I don't understand how this happened exactly? Could someone point me in the right direction?

Thanks
 
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Did you try actually computing the integrals? What did youget? Please show your work.
 
Orodruin said:
Did you try actually computing the integrals? What did youget? Please show your work.

What are y'^2 and z'^2? I don't know what to sub in for these (not sure what they represent?) so can't do the integral until I know them.
 
They are coordinates as shown in the figure.
 
Orodruin said:
They are coordinates as shown in the figure.
I understand that but I mean how would one integrate those terms with respect to m? They aren't constants?
 
They depend on where in the body you are.
 
Orodruin said:
They depend on where in the body you are.
Sorry for the late reply. I am still confused. I just want to know how they (mathematically) got from the left hand side to the right. I don't understand how integrating the left hand side yields the right hand side.
 
Use ##dm = \rho \, dx'dy'## and integrate over ##x'## and ##y'## with the appropriate boundaries. The value of ##\rho## in terms of the total mass ##m## can be inferred by computing the volume ##V## of the body and using ##\rho V = m##.
 

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