Infinite limit of inverse tangent series

flyerpower
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Homework Statement


Take the infinite limit of that sequence.
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Homework Equations





The Attempt at a Solution


I have no idea where to start from, hints and ideas would be greatly appreciated.

Thanks.
 
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hi flyerpower! :smile:

hint: (tanA - tanB)/(1 + tanAtanB) :wink:
 
tiny-tim said:
hi flyerpower! :smile:

hint: (tanA - tanB)/(1 + tanAtanB) :wink:


Ok, so tan(A-B)=(tanA-tanB)/(1+tanAtanB)

and A-B=arctan[(tanA-tanB)/(1+tanAtanB)

Now i think i should find some A and B so as :

tanA-tanB=x
and
tanA*tanB=k(k+1)*x^2

buuut i cannot still figure out what A and B should be
 
How about tan(A) =(k+1)x & tan(B) =kx ?
 
LOL, it was so obvious, thank you:)

It gives me pi/2 - arctg(x) which is arctg(1/x)

Thank you both!
 
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