Two particles(A and B) each of mass 10kg are attached to a massless rod on each on opposite ends of the rod. The rod is placed horizontally on a fulcrum. Particle A is 10 cm away from the fulcrum. And particle B is 70cm away from the fulcrum. The rod is now released. What is the magnitude of the initial acceleration of particle A? What is the magnitude of the initial acceleration of particle A? My solution so far B_torque - A_torque = mgb - mga = mg(0.7)-mg(0.1) =0.6mg Torque = Iα I = m(a^2 + b ^2) Thats the only thing I can think off right now. Totally stuck have no idea what to do. Wasn't in class when this lesson was given so i have no idea what i am doing.