Initial Velocity of the original superman

AI Thread Summary
To calculate the initial velocity of Superman leaping to an 85.5 m high building, the acceleration due to gravity (9.8 m/s²) should be used with the correct sign. The equation v2 = v1 + 2ad can be applied, where v2 is the final velocity (0 m/s at the peak), and a is the acceleration. It's noted that once Superman leaves the ground, his acceleration can be considered zero as he cannot exert additional force. Properly applying these principles will yield the initial velocity needed for the leap.
LunaFlores
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Homework Statement


The original superman leaps into the air to land on an 85.5 m high building. What was his intial velocity?
d = 85.5 m
v2 = 0
v1 = ?
a = 9.8 m/s2 (I'm not sure about this one so I just used acceleration due to gravity)

Homework Equations


v2 = v1 + 2ad (?)

The Attempt at a Solution


I'm really not sure what acceleration value to use for this or if I can solve it without using acceleration
 
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LunaFlores said:

Homework Statement


The original superman leaps into the air to land on an 85.5 m high building. What was his intial velocity?
d = 85.5 m
v2 = 0
v1 = ?
a = 9.8 m/s2 (I'm not sure about this one so I just used acceleration due to gravity)

Homework Equations


v2 = v1 + 2ad (?)

The Attempt at a Solution


I'm really not sure what acceleration value to use for this or if I can solve it without using acceleration

Unless Superman is on the Planet Krypton, you should use the acceleration due to gravity here on Earth, but make sure it has the proper sign.

Since he's leaping from the ground, it's approximately correct to say that Superman's acceleration can be taken as zero, since once his feet are in the air, he can no longer provide any additional force on the ground to increase his velocity.
 
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