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Integer proof

  1. Mar 2, 2008 #1
    1. The problem statement, all variables and given/known data
    Prove that for all x there exists and x if it is an element of the positive integers, then there is an integer y and an integer z.

    2. Relevant equations

    3. The attempt at a solution

    I know that the contrapositive would be "If there is not an element of the positive integers, then there is not an integer y or an integer z." I also know that positive integers=1,2,3,..........and integers=....-2, -1, 0, 1, 2,...........

    Could someone please give me a hint or show me what to do from here?

    Thank you very much
  2. jcsd
  3. Mar 2, 2008 #2


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    Can you rephrase that in a way that makes any sense whatsoever?
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