Integral from 0 to 5: Solve "Variable 't' is not Defined" Error

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Homework Statement



Int from 0 to 5:

te^(-e)dt

Homework Equations

The Attempt at a Solution

I did the integration by parts and got:

(-t)e^(-1)-e^05+e^0

I got it incorrect: "Variable 't' is not defined in this context"
 
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mshiddensecret said:

Homework Statement



Int from 0 to 5:

te^(-e)dt

Homework Equations

The Attempt at a Solution

I did the integration by parts and got:

(-t)e^(-1)-e^05+e^0

I got it incorrect: "Variable 't' is not defined in this context"

Just to be clear, are you trying to evaluate:

$$\int_{0}^{5} t(e)^{-e}dt$$

because if you are, this is a very trivial integral.
 
mshiddensecret said:
"Variable 't' is not defined in this context"

That message means that there should be no variable t in the final answer. It's a definite integral.
 
mshiddensecret said:

Homework Statement



Int from 0 to 5:

te^(-e)dt
Is the above a typo?
Could this be your integral?
$$\int_0^5 te^{-t}dt$$
 
Mark44 said:
Is the above a typo?
Could this be your integral?
$$\int_0^5 te^{-t}dt$$
Yeah. That's what it looks like.
 
@mshiddensecret, try to be more careful when you post. SteamKing and Dick were unable to help you because of this mistake.
 
Just a suggestion: Use the Preview button to check your posts before submission. It's helped me avoid more than a few mistakes.
 
Mark44 said:
Is the above a typo?
Could this be your integral?
$$\int_0^5 te^{-t}dt$$
mshiddensecret said:
Yeah. That's what it looks like.
Show us the work you did in integrating by parts...
 
I agree with Mark44, it seems like you went wrong somewhere in the integration by parts.
## \int_a^b u dv = \left. uv \right|_a^b - \int_a^b v du ##
The first term in your answer above looks like you may have misinterpreted ##\left. uv \right|_a^b##
Did you use ## u = t, \, dv = e^{-t}dt##?
 
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