- #1
americanforest
- 223
- 0
Hey guys,
By what rules is the integral of
[tex]\frac{cos(t)}{1+9sin^2(t)}=\frac{1}{3}tan^{-1}(sin(3t))[/tex]
I know this is right, but I have no idea why and can't find any trig identities to help. Thanks.
By what rules is the integral of
[tex]\frac{cos(t)}{1+9sin^2(t)}=\frac{1}{3}tan^{-1}(sin(3t))[/tex]
I know this is right, but I have no idea why and can't find any trig identities to help. Thanks.