Partial Fraction Decomposition for Integrating Rational Functions

JamesGoh
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Im trying to find the integral of ( sec(t)^2 ) / ( (tan(t)^3) + (tan(t)^2) ). I've managed to get the
integral into the form

1 / (u^3 + u^2) where u = tan(t), however I am having difficulty proceeeding from there.

Could someone take a look at the working out I have attached and let me know what I am not doing right? (the correct answer is written in red pen on 2nd page)
 

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In order to evaluate ##\int\frac{1}{u^2(u+1)}\ du##, you want to use partial fraction decomposition, and that alone. You do not need to do any integration by parts. You have a correct general form $$\frac{1}{u^2(u+1)}=\frac{A}{u^2}+\frac{B}{u+1}+\frac{C}{u}$$ for the PFD, but then it looks like it all goes south after that, and you just gave up on that idea. Stick with that Idea.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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