Integral P(r) Normalization: Find Constant

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p(r) is proportional too (1/r)Exp(-r/R). r is the variable.

I'm trying to normalise this function (R is proton radius), so I'm trying to get the integral between infinity and -infinity = 1 so I can find the normalisation constant. I don't know how to do this integral I've tried by parts but it seems there are discontuinities. I'm probably missing something obvious, can sombody point me on the right track?
 
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:wink: Non-elementary solution.

http://mathworld.wolfram.com/ExponentialIntegral.html"
 
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Thanks, I can't see how to normalise this function however.
 
Probably you're integrating from r=0 to r=\infty, not over the whole range of r.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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