Integrating Force: Derive Distance L for AP Question

AI Thread Summary
The discussion revolves around deriving the distance L that a dart penetrates into a block of wood, given that the force exerted by the block is proportional to the dart's velocity and acts in the opposite direction. Participants emphasize the necessity of integration due to the non-constant nature of the force, which complicates the use of standard kinematic equations. Suggestions include using Newton's second law to express force as a derivative of velocity rather than position. Additionally, breaking the problem into small time intervals allows for approximating changes in velocity and force, which can be calculated iteratively. Overall, integration is essential for solving this problem effectively.
aber
Messages
8
Reaction score
0
This last part of an AP questions is giving me some trouble, mostly because i involves integrating and i never took Calculus.

Part D: The dart is now shot into a block of wood that is in a fixed place. The block exerts a Force F on the dart that is proportional to the dart's Velocity V and in the opposite direction, that is F=-bv, where b is a constant. Derive and expression for the distance L that the dart penetrates into the block, in terms of m (mass), v (initial), and b.

Since the Force -bv is not constant, i can't figure out how to use the kinetic energy 1/2mv^2 to solve for distance, i would think you would need X=Xknot+vknotT+1/2aT^2.
 
Physics news on Phys.org
aber said:
Since the Force -bv is not constant, i can't figure out how to use the kinetic energy 1/2mv^2 to solve for distance, i would think you would need X=Xknot+vknotT+1/2aT^2.
As you seem to realize, you need to be able to integrate to solve this problem. That kinematic equation is only good for uniformly accelerated motion, which is not the case here.

If you want to try your hand at integrating, here's a hint: \int F dt = \Delta (mv).
 
aber,

Here's another way to think about it. You have the equation F = -vb. What does Newton's 2nd law say about F? Can you rewrite what it says as a derivative of v intstead of x?
 
jdavel: i don't know how to derive...
Doc Al: Would it be change in F dt= change in MV, F= MV-M0/t=MV/t? t=2L/3V, F= 3MV^2/2L
 
You have learned that acceleration is the rate of change of velocity. Since you know the initial velocity, you know the initial force. That force is going to reduce the velocity. If you break the problem up into small intervals of time, you can get a good approximation of the change in velocity in one interval of time by assuming the intial force is constant for the first interval and calculating the change in velocity resulting from that force applied in that short time. At the end of that time, the dart will have a lower velocity, so you can calculate the reduced force and assume it is constant for the next little interval of time, leading to a lower velocity and a lower force for the next interval, etc., etc. If you know how to use a spreadsheet or program a calculator or computer, you can make the times intervals very small and make the approximation as good as you like.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top