Integrating Square Root of a Rational Function with Variable Substitution

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How to integrate below?

$$\int \sqrt{\frac{r^{2}-x^{2}+x^{2}}{r^{2}-x^{2}}} dx$$

neither if u = r^2 - x^2 nor u = x^2 will get the result.
 
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Try u=x/r, and simplify, it should become a standard integral (solvable with formulas, or with a trigonometric substitution)
 
vee6 said:
How to integrate below?

$$\int \sqrt{\frac{r^{2}-x^{2}+x^{2}}{r^{2}-x^{2}}} dx$$

neither if u = r^2 - x^2 nor u = x^2 will get the result.
Is this really what you meant? Since -x^2+ x^2= 0 the is exactly the same as
|r|\int \frac{1}{\sqrt{r^2- x^2}}dx

The substitution x= sin(t) would be a stadard technique for this.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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