Integrating Trigonometric Functions: Secant and Tangent

  • Thread starter Thread starter jdawg
  • Start date Start date
  • Tags Tags
    Integration
jdawg
Messages
366
Reaction score
2

Homework Statement



∫secxtan3x dx

Homework Equations





The Attempt at a Solution


∫secxtanx(tan2x) dx
∫secxtanx(sec2x-1) dx

Is u supposed to equal secx?
 
Physics news on Phys.org
Du=Secxtanx
I like to rearrange my integral

∫(secx^2-1) secxtanx dx
------------(^ ^ Du^^)

Since you pulled out secxtanx as du.
and converted the remaining factors to secants.All you have to do now is
take the integral of
∫(secx^2-1) and that will be your answer
 

Attachments

  • Capture.JPG
    Capture.JPG
    11.5 KB · Views: 384
Thanks
 
No problem! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top