Integrating Using Partial Fractions

Jay9313
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Homework Statement


This is an arc length problem in three dimensions. I was given the vector r(t)=<et, 1, t> from t=0 to t=1


Homework Equations


Arc Length= \int |\sqrt{r&#039;(t)}| dt from t1 to t2
where |\sqrt{r&#039;(t)}| is the magnitude of the derivative of the vector

The Attempt at a Solution



I took the derivative and got the magnitude and simplified it down to
∫ √(e2t+1) dt
I then set u=e2t+1
I then simplified and substituted until I got to:∫\frac{\sqrt{(u)}}{u-1} du

My professor said to use partial fractions from here, but I'm not sure how to do that.
 
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Try one more substitution to get rid of the square root on top first. Then do partial fractions.
 
That's not really working at all
 
What did you try?
 
I split it up, and it made it worse, and I had to do long division, but I got an answer. It's nasty, but I got an answer.
 
Presumably, you ended up with something like ##\frac{v^2}{v^2-1}## after the substitution. A good technique to avoid doing long division is to add and subtract judiciously:
$$\frac{v^2}{v^2-1} = \frac{(v^2-1)+1}{v^2-1} = 1 + \frac{1}{v^2-1}.$$
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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