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[tex]\int_{1}^{2} \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)} dx[/tex]

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i already get theanswer [tex]\searrow -1.09 [/tex]

then, given that

[tex]

y = \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)}

find \frac{dy}{dx} [/tex] when x=-1

how to use the answer from previous stage to apply into this question?

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# Integration - 2

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