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## Homework Statement

Compute the area as an integral along the y-axis:

f(x) = x^2 - 6, g(x) = 6 - x^3

## Homework Equations

N/A

## The Attempt at a Solution

I solve for x in terms of y for both equations and end up with:

f(y) = +/-√(y+6), g(y) = (6-y)^(1/3)

I then look for interception points of the functions f(y) = g(y)

and I find y = -2.

My question is, if there is only one interception point how can I compute the area

between these two functions? I tried plugging into wolfram, and even it says

"cannot compute integral".

Am I reading the problem wrong? Or am I doing something wrong?

EDIT: When the question states "along the y-axis" does it perhaps mean the line x = 0 as a lower bound?

And then to just integrate from x = 0 to the point of interception (2)? That's the only way I can think of doing this.

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