Compute the area as an integral along the y-axis:
f(x) = x^2 - 6, g(x) = 6 - x^3
The Attempt at a Solution
I solve for x in terms of y for both equations and end up with:
f(y) = +/-√(y+6), g(y) = (6-y)^(1/3)
I then look for interception points of the functions f(y) = g(y)
and I find y = -2.
My question is, if there is only one interception point how can I compute the area
between these two functions? I tried plugging into wolfram, and even it says
"cannot compute integral".
Am I reading the problem wrong? Or am I doing something wrong?
EDIT: When the question states "along the y-axis" does it perhaps mean the line x = 0 as a lower bound?
And then to just integrate from x = 0 to the point of interception (2)? That's the only way I can think of doing this.