1. The problem statement, all variables and given/known data Compute the area as an integral along the y-axis: f(x) = x^2 - 6, g(x) = 6 - x^3 2. Relevant equations N/A 3. The attempt at a solution I solve for x in terms of y for both equations and end up with: f(y) = +/-√(y+6), g(y) = (6-y)^(1/3) I then look for interception points of the functions f(y) = g(y) and I find y = -2. My question is, if there is only one interception point how can I compute the area between these two functions? I tried plugging into wolfram, and even it says "cannot compute integral". Am I reading the problem wrong? Or am I doing something wrong? EDIT: When the question states "along the y-axis" does it perhaps mean the line x = 0 as a lower bound? And then to just integrate from x = 0 to the point of interception (2)? That's the only way I can think of doing this.