Integration by Partial Fractions

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SUMMARY

The integral of the function 1/((x+8)(x^2+16)) was analyzed using partial fraction decomposition. The user set up the equation as A/(x+8) + (Bx+C)/(x^2+16) and derived the equations A+B=0, 8B+C=0, and 16A+8C=1. The correct values for A, B, and C were determined to be A=1/10, B=-1/10, and C=4/5, but the user initially miscalculated the final integral, leading to an incorrect result. The error was identified in the algebraic manipulation of the equations for A, B, and C.

PREREQUISITES
  • Understanding of partial fraction decomposition
  • Knowledge of integration techniques, specifically for rational functions
  • Familiarity with algebraic manipulation of equations
  • Basic knowledge of logarithmic and arctangent functions
NEXT STEPS
  • Review the method of partial fraction decomposition in calculus
  • Practice integrating rational functions using various techniques
  • Study the properties and applications of logarithmic and arctangent functions
  • Explore common mistakes in algebraic manipulation and how to avoid them
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, and educators looking for examples of common errors in partial fraction decomposition.

cathy
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Homework Statement



1/ (x+8)(x^2+16)
Find the integral



Homework Equations



I keep getting this question wrong. Can someone check my steps?

The Attempt at a Solution



I set it up as
A/(x+8) + (Bx+C)/(x^2+16)

So I did, A(x^2+16)+ (Bx+C)(x+8)
and I did that and got
A+b=0
8B+C=0
16A+8C=1

By algebra, I solved for A, B, and C and got
A= 1/10
B= -1/10
C= 4/5

So I got 1/10ln(x+8) - 1/10∫x/(x^2+16) + 4/5∫1/(x^2+16)
and solving that out, I get 1/10ln(x+8) -1/20ln(x^2+16) + 1/5arctan(x/4)
which is not correct.
Where did I go wrong?
Thanks in advance.
 
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The linear equations A, B, and C satisfy are fine, but you didn't solve for A, B, and C correctly. If you plug in your values for A and C into the last equation, you'll see it's not satisfied.
 
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Oh I see my mistake. Such a simple error. Thank you.
 

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