Integration by Parts evaluation help

01010011
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Hi,
Can you tell me if I am on the right track with this problem. Thanks in advance.

Homework Statement


Evaluate the integral using integration by parts


Homework Equations


ln(2x + 1)dx


The Attempt at a Solution


ln(2x + 1)dx

= ln(2x + 1) * 1dx

Let U = ln(2x + 1)

therefore du = 1/(2x+1)

dv = 1dx

therefore v = x

Using the formula: \int udv = uv - \int vdu

= \int ln(2x + 1) * 1dx = ln (2x + 1)(x) - \int (x)(1/2x + 1)

If any of this is correct, I am now stuck at this point.
 
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01010011 said:
Let U = ln(2x + 1)

therefore du = 1/(2x+1)

Double check that differentiation :wink:

Other than that, it looks good so far. As a hint on how to continue, \frac{2x}{2x+1}=1-\frac{1}{2x+1}[/tex]
 
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