# Integration by parts?

## Homework Statement

Evaluate the indefinite integral.

∫(x + 3)/(x^2+6x) dx

## Homework Equations

This is an online hw prob. that covers sections integration by parts and substitution in indefinite integrals. it looks to me that it fits into the formula ∫udv=uv-∫vdu if you change the original equation to (x+3)*(x^2+6x)^-1

## The Attempt at a Solution

Doing this would give you u=x+3, dv=(x^2+6x)^-1, du=1, v=(-log(x+6)-log(x))/6

this however is not correct answer. Am I using the wrong method?

Am I using the wrong method?
You are missing an easier method. Take the derivative of the denominator and compare it to the expression in the numerator. Do you see an easy relation between the TWO? Now ask, what substitution makes sense?