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## Homework Statement

Evaluate the indefinite integral.

∫(x + 3)/(x^2+6x) dx

## Homework Equations

This is an online hw prob. that covers sections integration by parts and substitution in indefinite integrals. it looks to me that it fits into the formula ∫udv=uv-∫vdu if you change the original equation to (x+3)*(x^2+6x)^-1

## The Attempt at a Solution

Doing this would give you u=x+3, dv=(x^2+6x)^-1, du=1, v=(-log(x+6)-log(x))/6

the final answer becomes (x+3)((-log(x+6)-log(x))/6)-((-(x+6)log(x+6)+xlog(x)-2x-6)/6)

this however is not correct answer. Am I using the wrong method?