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Integration of Rational Functions by Partial Fractions?

  • #1
Integration of Rational Functions by Partial Fractions???

Ok I'm working on some homework problems and I don't even know how to do the first one, here is my problems and the steps that I did thus far ( I don't know if I did them right)

5x-13/(x-3)(x-2)= A/x-3 + B/x-2[tex]\rightarrow[/tex] ...5x-13= A(x-3)(x-2)B(x-2)(x-3)[tex]\rightarrow[/tex].... =(A+B)x2+(-5A-5B)x+(6A+6B)

That's how far I got, I don't know what to do next because in the textbook the next thing they do is equate the coefficients which I don't know how to do and other stuff ....please someone help if you know how to
 
Last edited:

Answers and Replies

  • #2
Char. Limit
Gold Member
1,204
13


Well, I'm not entirely sure what you did there, but remember that A+B is the coefficient of x^2, and what's the coefficient of x^2 on the left side of the equation? Then do the same for the other two powers of x.
 
  • #3


what's the coefficient of x^2 on the left side of the equation?
Sorry, I forgot to put in the x I overlooked that
 

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