Integration: Solve x^2-3x+2 Over x+1

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Homework Help Overview

The discussion revolves around the integration of the expression (x^2 - 3x + 2) / (x + 1). Participants are exploring methods to approach this integral within the context of calculus.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Some participants express uncertainty about how to begin the problem. Suggestions include dividing the polynomials to simplify the expression and breaking it into separate integrals. Others emphasize the importance of correctly identifying the nature of the expressions involved.

Discussion Status

Participants are actively discussing different methods to tackle the integration problem. Some guidance has been offered regarding polynomial division, and there is an ongoing exploration of how to simplify the integral.

Contextual Notes

There seems to be confusion regarding terminology, as some participants note that the expressions presented are not equations. This highlights a potential area of misunderstanding in the problem setup.

kingdomof
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Homework Statement



Int(x^2-3x+2)/(x+1)dx



Homework Equations





The Attempt at a Solution



I don't know where to start.
 
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Start by dividing the two polynomials. The resultant expression will be much simpler.
 
kingdomof said:

Homework Statement



Int(x^2-3x+2)/(x+1)dx



Homework Equations





The Attempt at a Solution



I don't know where to start.

Instead of trying to factor simply divide it into 3 different equations i.e.


[tex]\int \frac{x^{2}}{x+1}dx - \int \frac{3x}{x+1}dx + \int \frac{2}{x+1}dx[/tex]
 
djeitnstine said:
Instead of trying to factor simply divide it into 3 different equations i.e.


[tex]\int \frac{x^{2}}{x+1}dx - \int \frac{3x}{x+1}dx + \int \frac{2}{x+1}dx[/tex]
These aren't equations: they are expressions.

A much simpler approach is to do as jgens advised, and divide x^2 - 3x + 2 by x + 1, using long division.
 

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