Lancelot59
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With this particular problem you are given the functions y=x^{2}, y=4, and y=b.
The object is to solve for a value of b that will split the area between y=4 and y=x^{2} in half.
[PLAIN]http://www4c.wolframalpha.com/Calculate/MSP/MSP263419aghg2f97i2944e0000580a2hgi735b957c?MSPStoreType=image/gif&s=42&w=399&h=201
The approach I took was to include y=b in the integral, and then subtract the top half from the bottom half and equate that to zero.
\int_{-2}^{2} {(4-x^2-b)}\ = \int_{-2}^{2} {(b-x^2)}
All I did then was solve the integrals, and isolate b to get an answer of 4. However the answer is 4^2/3. I'm also stuck on a similar problem where I need to solve for a constant where two functions have to enclose a specific area.
The object is to solve for a value of b that will split the area between y=4 and y=x^{2} in half.
[PLAIN]http://www4c.wolframalpha.com/Calculate/MSP/MSP263419aghg2f97i2944e0000580a2hgi735b957c?MSPStoreType=image/gif&s=42&w=399&h=201
The approach I took was to include y=b in the integral, and then subtract the top half from the bottom half and equate that to zero.
\int_{-2}^{2} {(4-x^2-b)}\ = \int_{-2}^{2} {(b-x^2)}
All I did then was solve the integrals, and isolate b to get an answer of 4. However the answer is 4^2/3. I'm also stuck on a similar problem where I need to solve for a constant where two functions have to enclose a specific area.
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