Interesting Problem, Not sure where to begin.

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The discussion revolves around a physics problem involving sound waves entering a window in a theater, where two people positioned along a wall hear no sound. The scenario is identified as a single slit diffraction problem, with calculations suggesting that the first minima occurs at a distance of 10.5 feet from the center of the wall. There is a clarification regarding the use of formulas, with one participant asserting that the formula pertains to the first minima, while another questions if it relates to the first maxima instead. The conversation emphasizes the importance of correctly applying diffraction principles to determine the minimum distance between the two individuals. Understanding the distinction between single and double slit diffraction is crucial for solving the problem accurately.
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I need some help getting started on this one:

Sound waves of frequency 582 Hz enter a window 1.3m wide.

The window is in the exact center of one wall of a theater 24m by 12m.

The window is 12m from the opposite wall, along which is a row of seats occupied by people.

The theater is acoustically prepared to prevent the reflection of sound waves, and the speed of sound is 330 m/s.

Two people, on each side of a line directly in front of the window, in the row along the wall hear no sound.

What minimum distance are they from each other?
 
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Mbsams said:
Sound waves of frequency 582 Hz enter a window 1.3m wide.
The window is in the exact center of one wall of a theater 24m by 12m.
The window is 12m from the opposite wall, along which is a row of seats occupied by people. The theater is acoustically prepared to prevent the reflection of sound waves, and the speed of sound is 330 m/s.

Two people, on each side of a line directly in front of the window, in the row along the wall hear no sound. What minimum distance are they from each other?
This is a 'single slit' diffraction problem. The first minima on the far wall will occur at a point x from the middle of the wall where x = \lambda L/a where a is the slit width and L is the distance from the window to far wall.

I get 10.5 feet.

AM
 
Wouldn't that correspond to the first maxima and not minima?
 
Mbsams said:
Wouldn't that correspond to the first maxima and not minima?
I think the formula is for the first minima - this is single slit diffraction. You may be using double slit diffraction. I am sure you can check this.

AM
 
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