Where is the Maximum Intensity of Radio Signal from Two Towers?

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The discussion revolves around determining the maximum and minimum intensity of radio signals from two towers positioned 400 meters apart, transmitting in phase at a frequency of 1 MHz. For maximum intensity, listeners located 20 km north of the transmitter should be positioned at specific angles relative to the towers. Conversely, if the towers transmit in opposite phase, the minimum intensity will occur in different directions north of the transmitter. The original poster expresses confusion about how to approach the problem, seeking guidance on visualizing the scenario and applying relevant equations. The conversation emphasizes the need for a clear understanding of wave interference patterns to solve the problem effectively.
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Homework Statement


Heres the question:
Two towers of a radio station are 4.00 x 10^2 m apart along and east-west line. The towers act essentially as point sources, radiating in phase at a frequency of 1.00 x 10^6 Hz. Radio waves travel at 3.00 x 10^8 m/s.

a) In which directions is the intensity of the radio signal at a maximum for listeners 20k north of the transmitter (but not necessarily directly north of it)?

b) In which directions would you find the intensity at a minimum, north of the transmitter, if the towers were to start transmitting in opposite phase?


Homework Equations


|PnS1 - P2S2| = (n -1/2)lambda

Sin theta n = (n-1/2)lambda/d

The Attempt at a Solution



I have no idea =/. Honestly I've worked on it for 30 minutes and can't even figure out where to start.

Thanks
 
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