- #1

- 394

- 2

[tex]\int3/(3x-2) dx[/tex] from 0 to -1 (top to bottom).

I change the equation to [tex(1/x - 3/2) dx[/tex]

then integrated ln x-3/2x, but ln x at 0 is undefined.

The text book shows it as becoming ln (3x-2), but I'm not completely understanding how to get to that.