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## Main Question or Discussion Point

Hi all,

I read that the internal entropy change of a system ([tex]\Delta[/tex]S

∆Ss= 3/2(Nk(ln(Tr/Ts) - ((Tr – Ts )/ Tr )))

can achieve this.

Note:

∆Ss= change in entropy for system

Tr=Temperature of reservoir

Ts=Temperature of system

I have played around with it for a while but dont seem to be able to get this result.

Thanks everyone :)

I read that the internal entropy change of a system ([tex]\Delta[/tex]S

_{i}) for a non-quasistatic process where a reservoir cools or heats the system, where N and V are fixed and no work is done is approximately equal to ([tex]\Delta[/tex]T)^{2}, when the difference between T_{Reservoir}and T_{system}is small. The book said that expanding the logarithm in:∆Ss= 3/2(Nk(ln(Tr/Ts) - ((Tr – Ts )/ Tr )))

can achieve this.

Note:

∆Ss= change in entropy for system

Tr=Temperature of reservoir

Ts=Temperature of system

I have played around with it for a while but dont seem to be able to get this result.

Thanks everyone :)