A Interpretation of covariant derivative of a vector field

Pentaquark5
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On Riemannian manifolds ##\mathcal{M}## the covariant derivative can be used for parallel transport by using the Levi-Civita connection. That is

Let ##\gamma(s)## be a smooth curve, and ##l_0 \in T_p\mathcal{M}## the tangent vector at ##\gamma(s_0)=p##. Then we can parallel transport ##l_0## along ##\gamma## by using
$$ \nabla_{\gamma'(s)}l(s)=0 .$$
However, I'm having trouble applying this knowledge to the following case (quote from my script):

Let ##e_0:=\dot{\gamma}## and ##e_1 \perp e_0## be unit vectors. Let further ##S## be the ##2##-dimensional submanifold of ##\mathcal{M}## obtained by shooting null-geodesics with initial direction ##l(0):=e_0+e_1## from all points along the curve ##\gamma##.
Imposing affine parameterisation, this defines on ##S## a vector field ##l## tangent to those geodesics, solution of the equation
$$\nabla_l l=0.$$
I interpret this equation as the parallel transport of ##l## along ##l##, but that does not really coincide with the description given in my script.

Could anybody help me make sense of this equation? Thanks
 
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Pentaquark5 said:
I interpret this equation as the parallel transport of lll along lll, but that does not really coincide with the description given in my script.
Why not? A geodesic is a curve whose tangent vector is parallel transported along the curve itself.

Also, you seem to be dealing with a pseudo-Riemannian manifold, not a Riemannian manifold. A Riemannian manifold does not have any non-zero null vectors.
 
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Ah, thank you I don't know what went wrong in my head there. And you are of course correct in noting that ##\mathcal{M}## is pseudo Riemannian.

Thanks!
 
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