Intro to Algebra, Symmetric group # of elements of order 4 in S6

In summary, to find the number of elements of order 4 in S6, we first need to determine the number of 4-cycles in the symmetric group. This can be done by choosing 4 elements out of the 6 in the group, resulting in 15 possible combinations. Then, we can determine the number of possible 4-cycles on each combination, which is equal to the number of 4-cycles in S4. Additionally, there are also elements of the form (abcd)(ef) and (abcd) in the group, which can be calculated by choosing 4 elements and then determining the number of possible combinations for the remaining 2 elements. Combining these methods, we can find the total number of
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Homework Statement



How many elements of order 4 are in S6? (symmetric group with order 6)

Homework Equations





The Attempt at a Solution



So, the different forms of elements with order 4 in S6 are

(abcd)(ef), (abcd)

from there I am sunk on how to calculate. I know there are 6! = 720 total elements in S6.
 
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  • #2
well, first, how many 4-cycles are there?

first, we have to pick 4 elements to permute out of 6. how many ways are there to choose 4 elements out of 6?

let's say we've picked our 4: {a,b,c,d}.

how many distinct 4-cycles can you make on that set (this should be the same number of 4-cycles as we have in S4, right?).

that should help you with the "pure" 4 -cycles.

now, suppose you have (a b c d)(e f).

once we've chosen a,b,c,d (step one in counting the 4-cycles), do we really have any choice as how to choose e and f? and given any two elements of {1,2,3,4,5,6}, say, j and k, how many transpositions can be made from j and k? if you think about this the right way, you don't even have to count the 4+2 cycles.
 

1. How do you determine the order of a symmetric group?

The order of a symmetric group is equal to the number of elements in the group, which is given by the formula n!, where n is the number of elements in the group. In the case of S6, the order would be 6!, which is equal to 720.

2. What is the meaning of "order 4" in symmetric groups?

The order of an element in a symmetric group represents the number of times the element must be multiplied by itself to get the identity element. In other words, it is the smallest positive integer k such that g^k = e, where g is the element and e is the identity element.

3. How do you find the elements of order 4 in S6?

The elements of order 4 in S6 can be found by looking for permutations (or rearrangements) of the elements in the group that, when multiplied by themselves 4 times, result in the identity element. These elements can be found by using the cycle notation method or the multiplication table method.

4. Can the number of elements of order 4 in S6 be determined without listing them all?

Yes, the number of elements of order 4 in S6 can be determined using the formula n!/lcm(4, n), where n is the number of elements in the group. In this case, n=6, so the formula would be 6!/lcm(4, 6) = 720/12 = 60 elements of order 4 in S6.

5. Why is it important to know the number of elements of order 4 in S6?

Knowing the number of elements of order 4 in S6 is important in understanding the structure and properties of the group. It can also be useful in solving problems related to permutations and symmetric groups, such as finding subgroups or determining the number of possible arrangements of a given set of elements.

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