LaTeX Introducing LaTeX Math Typesetting

gnome · Feb 9, 2005

Why doesn't this work? All I'm trying to do is get 2 left-aligned columns. First I was trying to do it using {array}{cc} formatting similar to the conditional equations up above. That didn't work so I tried this {equation*} layout which is also going haywire. When I was testing a little while ago, I'm pretty sure the same code (but with a smaller amount of content) worked almost correctly; only the first column was right- instead of left-aligned. Now it doesn't work at all.

To accomplish this, the formula will be built up from 3 types of variables, specifically:
\begin{equation*}\begin{split}\mbox{Variable} \quad &\mbox{Meaning}\\ Q[i,k] \quad &\mbox{At time i, M is in state q_k}\\ H[i,j] \quad &\mbox{At time i, the read-write head}\\ &\mbox{ is scanning tape square j}\\ S[i,j,k] \quad &\mbox{At time i, the contents of}\\ &\mbox{tape square j is symbol s_k}\end{split}\end{equation*}

OK this is really crazy; sometimes this works, and sometimes it doesn't, yet it's the same code structure as above:
\begin{equation*}\begin{split}\mbox{Variable} \quad &\mbox{Meaning}\\ Q[i,k] \quad &\mbox{At time i the read-write head blah blah blah}\\ &\mbox{blah blah blah}\\ H[i,j] \quad &\mbox{At time i}\end{split}\end{equation*}

jcsd · Feb 9, 2005

try {ll} instead {cc}, (that's how I managed to get the conditonal equation aligned).

gnome · Feb 9, 2005

Nope. It seems to make no difference whether I format it using {array}{cc} or {array}{11} or {equation*}{split}, \mbox{...} or \text{...]. For example:

To accomplish this, the formula will be built up from 3 types of variables, specifically:
\begin{array}{11}\mbox{Variable} & \mbox{Meaning}\\ Q[i,k] &\mbox{At time i, M is in state q_k}\\ H[i,j] &\mbox{At time i, the read-write head}\\ &\mbox{ is scanning tape square j}\\ S[i,j,k] &\mbox{At time i, the contents of}\\ &\mbox{tape square j is symbol s_k}\end{array}

jcsd · Feb 9, 2005

It's not a 1 it's an 'l' and you need one for each row:

edited to add: hmm I can't see anything wrong with this perhaps it's just too big.

gnome · Feb 9, 2005

(I think it's just any series of characters {xxx}, {111}, {iii}, whatever, not some particular one; and isn't it one for each COLUMN, not row?)

Edited to remove my witty(?) remark about the part of your post that you deleted.

jcsd · Feb 9, 2005

No, it's one for each row and 'c' is for centre 'l' is for left I guess.

edited to add: actually you're right but {ll}, {cc} or {rr} is the justifcation.

jcsd · Feb 9, 2005

This one works and it's simlair:

\begin{array}{lr}\mbox{yoink}&\mbox{double-yoink}\\G[i,j]&\mbox{yes}\\H[k,l] &\mbox{no}\\&\mbox{what?}\end{array}

I reckon then it must be thta it's just too big as there's a limit to the size of the code.

gnome · Feb 9, 2005

Good find!

That should be helpful.

gnome · Feb 9, 2005

That's it!

\begin{array}{ll}\mbox{Variable} & \mbox{Meaning}\\ Q[i,k] &\mbox{At time i, M is in state}\, q_k\\ H[i,j] &\mbox{At time i, the read-write head}\\ &\mbox{is scanning tape square j}\\ S[i,j,k] &\mbox{At time i, the contents of}\\ &\mbox{tape square j is symbol}\, s_k\end{array}

\mbox{testing another sub_sc_rip_t}

Building on jcsd's find:
the charaters in the brackets after {array} must be
{lll} (that lower-case L's) to left-align
{rrr} to right-align
{"any characters"} to center the text in each column (one char for each column)

Also: apparently subscript like q_k can't be used in \mbox in an array, although it can be used in \mbox when it's not part of an array.

Now I can get back to my "real" post.

Thanks.

Norman · Feb 14, 2005

Wick Contraction in LaTeX

Wick Contraction-

http://www.fzu.cz/~kolorenc/tex.php

This website has 2 or 3 possible implementations for Wick Contractions in QFT. I have not tried any, but will let you know how they work!

ramollari · Feb 15, 2005

Simple question.

Hi everybody,
Does anyone know how do I write a vector quantity, such as an F with an arrow up? I'm not so skilled in Latex.
Thanks

jcsd · Feb 15, 2005

\vec{F}

\vec{F}

ramollari · Feb 15, 2005

OK, let me try once.

 \sum\vec{F}_e_x_t = M\vec{a}_c_m

ramollari · Feb 15, 2005

Thanks jcsd!

Gary King · Feb 16, 2005

How do I create the 'inverse' symbol?

z-component · Feb 17, 2005

Like cos\theta^{-1}?

jcsd · Feb 17, 2005

inverse is just ^{-1}, so the (muplicative) inverse of a is a^{-1}, for an inverse function like cos you want \cos^{-1}\theta

The Divine Zephyr · Feb 21, 2005

\begin{array}P=A(1+\frac{r}{100})^n \\ \sqrt[n]{\frac{P}{A}}=\frac{r+100}{100} \\ r=100\sqrt[n]{\frac{P}{A}}-100\end{array}

Norman · Feb 22, 2005

Norman said:

Wick Contraction-

http://www.fzu.cz/~kolorenc/tex.php

This website has 2 or 3 possible implementations for Wick Contractions in QFT. I have not tried any, but will let you know how they work!

The simple_wick.tex file works very well. I could not get the other one to work. I also did not have any of the problems the author gives for simple_wick.tex.

Cheers

Orion1 · Feb 22, 2005

expired post...

Davorak · Feb 25, 2005

I have a question
How much Tex is to much tex?

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Davorak · Feb 25, 2005

That was not too much tex.

Limit is 20000 characters, interesting.

5 sin(2x) +5 x 0 to 10
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hmm can not put things too close together.

I am having trouble using negative number. I should just displace everything.
What is a better way to do these graphs, so they take fewer commands?

Davorak · Feb 25, 2005

10 BesselJ[0,z]

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10 BesselJ[1,z]

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\strecke{84.237,27.1585}{84.5307,27.2363} \strecke{84.5307,27.2363}{84.6651,27.2642} \strecke{84.6651,27.2642}{84.8106,27.2888} \strecke{84.8106,27.2888}{85.0744,27.3187} \strecke{85.0744,27.3187}{85.3312,27.3299} \strecke{85.3312,27.3299}{85.5675,27.3244} \strecke{85.5675,27.3244}{85.8008,27.3042} \strecke{85.8008,27.3042}{86.0187,27.2722} \strecke{86.0187,27.2722}{86.2577,27.2226} \strecke{86.2577,27.2226}{86.514,27.1525} \strecke{86.514,27.1525}{87.0372,26.9555} \strecke{87.0372,26.9555}{87.5143,26.7137} \strecke{87.5143,26.7137}{88.5922,25.9533} \strecke{88.5922,25.9533}{89.7652,24.801} \strecke{89.7652,24.801}{91.8981,21.9032} \strecke{91.8981,21.9032}{95.8259,14.3398} \strecke{95.8259,14.3398}{100.,4.3473} \end{picture}

JesseM · Mar 4, 2005

Why does the first one work while the second one is messed up?

\frac{2AB}{t^{'}_A - t_A} = c

\frac{2AB}{{t^'}_A - t_A} = c

anomoly · Mar 15, 2005

How would i go about getting the Amp to space a few characters away from the t(not) symbol?
I = \sqrt {[\frac {22.6T + 0.088t -490.58} {5 * 10^{-5} * t}] * t_{0}} Amp

dextercioby · Mar 15, 2005

JesseM said:

Why does the first one work while the second one is messed up?

\frac{2AB}{t^{'}_A - t_A} = c

\frac{2AB}{{t^'}_A - t_A} = c

Because you screwed up the code.Specifically,because your first code differs from the second through misplaced "{" which changes the way the "\frac" would work...

Daniel.

SergejVictorov · Mar 16, 2005

\lim_{\substack{x\rightarrow 0\\}} f(x,y)

quantumdude · Mar 20, 2005

I've got a question: Is it possible to make Feynman diagrams with our LaTeX hack? If not, would it be terribly difficult to create?

Thanks,

The Divine Zephyr · Mar 26, 2005

A=60+(S+\Delta P) \times \frac{L_2}{L_1}

gnome · Mar 26, 2005

anomoly said:

How would i go about getting the Amp to space a few characters away from the t(not) symbol?
I = \sqrt {[\frac {22.6T + 0.088t -490.58} {5 * 10^{-5} * t}] * t_{0}} Amp

I = \sqrt {[\frac {22.6T + 0.088t -490.58} {5 * 10^{-5} * t}] * t_{0}} \quad Amp

If you want it still farther away, use \qquad instead of \quad.
If you want it closer, use \;

hellfire · Mar 31, 2005

I posted this today in the cosmology forum:

dt = \frac{da}{H_0 \left(\frac{\Omega_{m,0}}{a} + a^2 \Omega_{\Lambda,0}\right)^{\frac{1}{2}}}

How can I made that the first "Omega" and "a" have the same size than the second?

dextercioby · Mar 31, 2005

U can't.Note that the whole fraction must be on equal footing a^{2}Omega...That means that the denominator & the numerator would be smaller than they'd be without the fraction line.

Daniel.

robphy · Mar 31, 2005

Use \displaystyle

dt = \frac{da}{H_0 \left(\displaystyle\frac{\Omega_{m,0}}{a} + a^2 \Omega_{\Lambda,0}\right)^{\frac{1}{2}}}

dextercioby · Mar 31, 2005

Yikes,i guess I'm still a rookie... :redface:

Daniel.

bomba923 · Apr 2, 2005

\begin{array}{l} Would{\rm }it{\rm }be{\rm }O.K{\rm }to{\rm }write{\rm }complete{\rm }posts{\rm }in{\rm }LaTex, \\ without{\rm }math{\rm }in{\rm }them \ldots {\rm }just{\rm }writing? \\ \end{array}

NOt that I can---but what if

?

hellfire · Apr 2, 2005

robphy said:

Use \displaystyle

Thank you!

richnfg · Apr 2, 2005

v = 0.13 

 P = \frac{1}{f}

richnfg · Apr 3, 2005

/mean=\frac{\sum x}{n}

robphy · Apr 3, 2005

bomba923 said:

 \begin{array}{l} Would{\rm }it{\rm }be{\rm }O.K{\rm }to{\rm }write{\rm }complete{\rm }posts{\rm }in{\rm }LaTex, \\ without{\rm }math{\rm }in{\rm }them \ldots {\rm }just{\rm }writing? \\ \end{array}

NOt that I can---but what if ?

You probably wanted to put the extra backslash to escape the space {\rm\ } to get
 \begin{array}{l} Would{\rm\ }it{\rm\ }be{\rm\ }O.K{\rm\ }to{\rm\ }write{\rm\ }complete{\rm\ }posts{\rm\ }in{\rm\ }LaTex, \\ without{\rm\ }math{\rm\ }in{\rm\ }them \ldots {\rm\ }just{\rm\ }writing? \\ \end{array}

You could just write it in an mbox
 \mbox{ Would it be O.K to write complete posts in \LaTeX, \\ without math in them \[\ldots\] just writing? } 
or in a verbatim environment
 \begin{verbatim} Would it be O.K to write complete posts in LaTeX, without math in them... just writing? \end{verbatim} 

However, I think it is probably discouraged to post like this.

bomba923 · Apr 7, 2005

The quadratic formula:

\begin{gathered} ax^2 + bx + c = 0,\\ x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }} {{2a}} \hfill \\ \end{gathered}

bomba923 · Apr 18, 2005

Brachistochrone Equation:
{\left\{ \begin{gathered} x = r\left( {\theta - \sin \theta } \right) \hfill \\ y = r\left( {1 - \cos \theta } \right) \hfill \\ \end{gathered} \right\}}

OlderDan · Apr 20, 2005

chroot said:

Whenever you want to include a graphic on the same line with your text, like C H_4 or G_\textrm{diffeo} or y = mx + b, you should use [ itex ]...[ /itex ] instead of [ tex ]...[ /tex ]. The "i" means "inline."

Click on each of the examples above to "learn by example."

If you have questions or comments about this site addition, you are welcome to post them here!

Good luck, and enjoy the system.

- Warren

I came looking specifically because my "inlines" were not in line. Glad to find this, but even with the itex the graphic is still raised. Is there a trick for lowering it more if you want to?

Edit

I am on a different machine now, and things look different. The inline text here does look inline. It is some local setting on my computer making the difference.

twoflower · Apr 23, 2005

twoflower said:

 blablablah \\ newlineblabla

Why doesn't \\ insert a new line for me?

Starship · Apr 29, 2005

Problems with brackets:

\left(\begin{array}{cc}\frac{\partial u}{\partial x}&\frac{\partial \nu}{\partial x}\\ \frac{\partial \nu}{\partial x}&\frac{\partial u}{\partial x}\end{array}\right)

\phi(x,y)

\frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu^2} = 0

w = u(x,y) + i\nu(x,y)

\frac{\partial \phi}{\partial x} = \frac{\partial \phi}{\partial u} \frac{\partial u}{\partial x} + \frac{\partial \phi}{\partial \nu} \frac{\partial \nu}{\partial x}

and

\frac{\partial \phi}{\partial y} = \frac{\partial \phi}{\partial u} \frac{\partial u}{\partial y} + \frac{\partial \phi}{\partial \nu} \frac{\partial \nu}{\partial y}

A second differentiation of these yields the results:

\frac{\partial^2 \phi}{\partial x^2} = \frac{\partial \phi}{\partial u} \frac{\partial^2 u}{\partial x^2} + \left ( \frac{\partial^2 \phi}{\partial u^2} \frac{\partial u}{\partial x} + \frac{\partial^2 \phi}{\partial \nu \partial u} \frac{\partial \nu}{\partial x} \right ) \frac{\partial u}{\partial x} + \frac{\partial \phi}{\partial \nu} \frac{\partial^2 \nu}{\partial x^2} + \left ( \frac{\partial^2 \phi}{\partial u \partial \nu} \frac{\partial u}{\partial x} + \frac{\partial^2 \phi}{\partial \nu} \frac{\partial \nu}{\partial x} \right ) \frac{\partial \nu}{\partial x}

Adding:

\frac{\partial^2 \phi}{\partial x^2} + \frac{\partial^2 \phi}{\partial y^2} = \frac{\partial \phi}{\partial u} \left ( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} \right ) + \frac{\partial^2 \phi}{\partial u^2} \left [ \left ( \frac{\partial u}{\partial x} \right )^2 + \left ( \frac{\partial u}{\partial y} \right )^2 \right ] + 2 \frac{\partial^2 \phi}{\partial u \partial \nu} \left ( \frac{\partial u}{\partial x} \frac{\partial \nu}{\partial y} \right ) + \frac{\partial \phi}{\partial \nu} \left ( \frac{\partial^2 \nu}{\partial x^2} + \frac{\partial^2 \nu}{\partial y^2} \right ) + \frac{\partial^2 \phi}{\partial \nu^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( \frac{\partial \nu}{\partial y} \right )^2 \right ]

w = u + i\nu

\frac{\partial^2 \phi}{\partial x^2} + \frac{\partial^2 \phi}{\partial y^2} = \frac{\partial^2 \phi}{\partial u^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( -\frac{\partial \nu}{\partial x} \right )^2 \right ] + \frac{\partial^2 \phi}{\partial \nu^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( \frac{\partial u}{\partial x} \right )^2 \right ] = \left [ \left ( \frac{\partial u}{\partial x} \right )^2 + \left ( \frac{\partial \nu}{\partial x} \right )^2 \right ] \left ( \frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu} \right ) = |f'(z)|^2 \left ( \frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu^2} \right )

bomba923 · Apr 30, 2005

Just redefining an earlier problem I had (Do NOT pay attention to this!

)

{\text{Let}} f_n \left( t \right) = \left\{ \begin{gathered} x_n \left( t \right) \hfill \\ y_n \left( t \right) \hfill \\ z_n \left( t \right) \hfill \\ \end{gathered} \right\} , {\text{ }} {\text{continuous}} {\text{ }} \forall t \in \left( {a,b} \right)

At any moment t \in \left( {a,b} \right), a triangle can be defined by the set of points \left\{ {f_1 \left( t \right),f_2 \left( t \right),f_3 \left( t \right)} \right\}.
Find the exact volume generated by this triangle from t = a to t = b.

(Don't pay attention to this)

Moo Of Doom · May 4, 2005

a\xrightarrow{c}b

I can display things on top of arrows, but is it possible to display text under them (preferrably both above and below at the same time, actually)?

robphy · May 4, 2005

a \stackrel{c}{\longrightarrow} b

a \overset{c}{\longrightarrow} b

a \underset{d}{\longrightarrow} b

a \underset{d}{\overset{c}{\longrightarrow}} b

Moo Of Doom · May 4, 2005

Thankesy! :)

Dr.Brain · May 12, 2005

\sum \int \bigodot

extreme_machinations · May 16, 2005

F=GmM_e/r^2

Edit: You added an unnecessary "\" before the F and G, and left out the necessary "/" in your second bracket.

LaTeX Introducing LaTeX Math Typesetting

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