INverse of a function between topological spaces and continuity

stgermaine
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Homework Statement


Prove that if the inverse of a function between topological spaces maps base sets to base sets, then the function is continuous.


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The Attempt at a Solution


I really don't know how to do this. Wikipedia entry for 'base sets' redirects to Pokemon cards.
 
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Have you tried playing with the Pokemon cards?

Just kidding; the standard def. of continuity , AFAIK, is that f:X-->Y is continuous

iff.(def.) the inverse image of an open subset of Y is open in X. Do you know how

basic sets relate to open sets?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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