Inverting Amplifier: Calculate Peak Voltages & Currents

  • Thread starter Thread starter naspek
  • Start date Start date
  • Tags Tags
    Amplifier
AI Thread Summary
The discussion revolves around calculating peak voltages and currents for an inverting amplifier circuit. The user is uncertain about the formulas, particularly whether to use Vin = Vin(pp) / 2, which is confirmed as correct for peak voltage. The output voltage formula Vout(pp) = -(Rf / R1) Vin(pp) is also presented for verification. Additionally, the user inquires about using the voltage divider rule to calculate peak voltages across R1 and Rf, with suggested equations for current through both resistors. The conversation emphasizes the importance of correctly applying these formulas for accurate lab results.
naspek
Messages
176
Reaction score
0
Hey there.. this is my lab discussion.. which i'll attend it this coming monday..
however.. there are questions that I'm not sure the formula to calculate it..
i really hope u guys can varified or corrected my formula.. =)


Homework Statement


Vin(pp) = 1.0V

is it Vin = Vin(pp) / 2 ?

Vout(pp) = -(Rf / R1) Vin(pp)

What are the peak voltages across R1 and Rf?

Calculate the peak currents of R1 and Rf

Homework Equations



Current through R1 = Vin(pp)/R1

Current through Rf = Vout(pp)/Rf

to find peak voltage, can i use voltage divider rule?

VR1 = 10k/43k x Vin
VRf = 33k/43k x Vin


:smile:
 

Attachments

Physics news on Phys.org
pp means peak-to-peak
 
so.. my Vin = Vin(pp) / 2?
 
naspek said:
so.. my Vin = Vin(pp) / 2?

If Vin is the peak voltage, yes.
 

Similar threads

Back
Top