Engineering Inverting Op Amp Circuit: Calculating Output Voltage with Feedback Loop

AI Thread Summary
The discussion centers on calculating the output voltage of an inverting op-amp circuit using feedback loops. The user struggles with defining two currents and eliminating them to express Vout in terms of input voltages and resistances. They derive an equation for Vout but encounter difficulties relating Va to Vin and the resistances. Suggestions include correcting the feedback loop drawing and applying the properties of ideal op-amps, specifically that Va equals Vb in a negative feedback scenario. The conversation emphasizes simplifying the circuit by neglecting the influence of additional resistances due to the ideal amplifier assumption.
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Homework Statement



Write output voltage in terms of input voltages for the circuit drawn.

I drew the circuit and then feed back loop.
circuit-9_4 (1).png

Homework Equations



Ohms Law V=IR
Basic Properties of Op Amps (ideal), voltages are assumed equal at both inputs...

The Attempt at a Solution



The difficulty is that there should be two currents that need defining, but I'm not sure how to eliminate both of them. I wrote two equations for the current through the feedback loop and then equated to write Vout in temrs of the resistances and Va.

I_a = \frac{V_{out}-V_a}{R_2}
I_a = \frac{V_a-V_{out}}{R_1}
V_{out}=\frac{V_a-V_{in}}{R_1}R_2 +V_a

I can't figure out how to write Va in terms of Vin and the resistances at this point. The only other relationships between Va and other quantities come from the fact that V_b=I_bR_3 which means that V_a=I_bR_3 also, but I still need to get rid of the current Ib now, so that doesn't help much. I can't figure out what I'm missing. Any help would be great.
 
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There's a mistake in the feed back loop in my drawing, the ground at the end of R2 should not be there, that should be Vout.
 
You've listed one useful property for the op-amp in a negative feedback situation. What other property might be useful?
 
Have a look on the second equation. Obviously, it is wrong (Vout mixed-up with Vin).
More than that, you can forget the influence of R3 (because an ideal amplifier with infinite input resistance is assumed). Hence, you can set Va=Vb=0.
 
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