Ionic equation, question about how the answer is derived here?

  • Thread starter Thread starter land_of_ice
  • Start date Start date
  • Tags Tags
    Ionic
AI Thread Summary
The discussion clarifies the derivation of the ionic equation from the original chemical reaction involving hydrochloric acid and zinc. It explains that not all species in the ionic equation carry a charge; for instance, zinc (Zn) is neutral on the left side but becomes Zn2+ on the right after losing two electrons. This loss of electrons indicates a redox reaction, where oxidation and reduction occur simultaneously. The concept of "formal" charge is emphasized, highlighting that the ionic equation focuses on charged species rather than requiring every component to have a charge. Understanding these principles is essential for accurately interpreting ionic equations in chemistry.
land_of_ice
Messages
136
Reaction score
0
2HCL (aq) + Zn (s) ----->H2 (g) + ZnCl2 (aq)
Ionic equation
2H+ (aq) +2CL-(aq) +Zn (s) + Zn2+(aq) + +2CL-(aq)

above is the original equation and the next step is the ionic equation also above, why in the ionic equation don't they put charges on everything ? like the Zn, on the left side of the ionic equation part, the book has no charge on it ? Doesn't everything in the ionic equation get a charge?

one more question about this:
also, how did the Zn get a charge of 2+ on the right side then of the ionic equation?
 
Physics news on Phys.org
An ionic equation is a way of writing the equation focusing on the charged species ("ions"). That doesn't mean that everything in the equation has to have a charge.

What's really being written here, is the 'formal' charge of an atom---which is an "effective" charge. On the L.H.S. (left-hand side) the Zn is neutral---thus it has no charge. On the R.H.S. the Zn is no longer neutral---it lost 2 electrons to the hydrogen (which is missing from the R.H.S.). This is therefore a "redox" reactions (in which electrons are exchanged).
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top