Ionization and Affinity Values for Mg+2 and Cl(-1) in Chemical Equations

[viciousp]

Homework Statement

Using data from text determine the following values:
a. Electron Affinity of Mg+2
b. Ionization energy of Cl(-1)
c. Electron affinity of Cl(+1)
d. Ionization energy of Mg(-1)

Homework Equations

The Attempt at a Solution

I'm assuming that you can't find actual values and my book (Zumdahl 7e) doesn't state them but I kind of made generalizations.

a. I said less than 230 KJ/mole since it is a positive ion and thus it would be easier to add electrons and it possibly will release energy
b. Less than 1251.1 kJ/mole because there is more sheilding and thus easier to remove an electron
c. less than -349 kJ/mole because it would be easier to add electrons since its positive, thus more energy will be released
d. Less than 737.7 kJ/mole because there are more electrons and thus it is easier to remove one

Is my thought process correct?

 

[nate808]

Thank you for your question! I can provide some guidance on how to determine the values you are looking for.

a. The electron affinity of Mg+2 can be determined by looking at the electron configuration of Mg. Since Mg has a configuration of 1s2 2s2 2p6, it will have a stable octet when it loses two electrons to become Mg+2. This means that it will have a high electron affinity, as it will be very favorable for Mg to gain two electrons to achieve a stable octet. However, the exact value cannot be determined without experimental data.

b. The ionization energy of Cl(-1) can be determined by looking at the electron configuration of Cl. Since Cl has a configuration of 1s2 2s2 2p6 3s2 3p5, it will have a stable octet when it gains one electron to become Cl(-1). This means that it will have a low ionization energy, as it will be very favorable for Cl to gain one electron to achieve a stable octet. However, the exact value cannot be determined without experimental data.

c. The electron affinity of Cl(+1) can be determined by looking at the electron configuration of Cl. Since Cl has a configuration of 1s2 2s2 2p6 3s2 3p5, it will have a stable octet when it loses one electron to become Cl(+1). This means that it will have a high electron affinity, as it will be very favorable for Cl to gain one electron to achieve a stable octet. However, the exact value cannot be determined without experimental data.

d. The ionization energy of Mg(-1) can be determined by looking at the electron configuration of Mg. Since Mg has a configuration of 1s2 2s2 2p6, it will have a stable octet when it gains one electron to become Mg(-1). This means that it will have a low ionization energy, as it will be very favorable for Mg to gain one electron to achieve a stable octet. However, the exact value cannot be determined without experimental data.

Your thought process is on the right track, but it is important to note that without experimental data, it is difficult to determine the exact values for these properties. It is always best to consult reliable sources or conduct experiments to obtain accurate

 

[Blueshift5]

Yes, your thought process is correct. The ionization energy and electron affinity values for Mg+2 and Cl(-1) can vary depending on the specific conditions and compounds involved. However, your generalizations are reasonable based on the trends observed in the periodic table. Mg+2 has a smaller ionization energy compared to Mg, as it has already lost two electrons and is more stable in its ionic form. Likewise, Cl(-1) would have a lower electron affinity than Cl, as it has already gained an electron and is more stable in its ionic form.