Iron ball hanging from a scale and suspended

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When an iron ball is suspended in a glass of water, the scale reading decreases due to the buoyant force acting on the ball, which counteracts its weight. The volume of water remains unchanged because the volume displaced by the ball equals the volume of the ball itself. The weight of the glass of water, including the ball, is effectively the same as before the ball was submerged, as the buoyant force does not alter the overall weight. The tension in the thread supporting the ball accounts for the difference between the ball's weight and the buoyant force. Overall, the system's dynamics illustrate the principles of buoyancy and weight distribution in fluids.
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Iron ball hanging from a scale and suspended...

Iron ball hanging from a scale and suspended in a glass of water filled to the rim, what happens to the reading of the scale, volume of water, and weight of the glass of water?

The attempt at a solution: there's an FB that's equal to the weight of the water removed pushing on the ball upwards, then weight - FB is equal to the tension in the thread, which means weight is less, then reading is less, volume of water stays the same because the volume of the water removed is equal to the volume of the ball, weight of the glass is...i have no idea tbh!

please explain your answer! thanks :)
 
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