Iron Core Solenoid: Calculating Applied Field and Magnetisation

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Homework Help Overview

The discussion revolves around calculating the applied magnetic field and magnetisation for an iron core solenoid, given specific parameters such as the number of turns, current, and measured magnetic field strength.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the applied magnetic field using the formula for a solenoid and express confusion regarding the resulting magnetisation value. Questions arise about whether the calculated magnetisation is correct and what typical values for magnetisation in ferromagnetic materials should be.

Discussion Status

Some participants have provided guidance on the calculations and expressed that the numbers seem reasonable for iron. There is ongoing exploration of the implications of the calculated values, particularly regarding the magnitude of magnetisation.

Contextual Notes

Participants note a lack of reference values for typical magnetisation, which contributes to their uncertainty about the results. There is also mention of the surprising effectiveness of ferromagnetic materials in achieving high magnetisation from relatively small applied fields.

sa1988
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Homework Statement



Iron core solenoid, with 50 turns per cm (5000 per metre)
Current = 0.2A
Measured B field = 1.58T

Calculate:
i) The applied field, Bapplied
ii) The magnitude of magnetisation, M, of iron alloy

Homework Equations



For a long solenoid, Bapplied0nI
And, generally, B=Bapplied0M

The Attempt at a Solution



I'm actually confused mainly on the first part because the answer isn't as it seems.

For a solenoid, the applied field is:
B=μ0nI

So I get B = 1.26E-6 * 5000 * 0.2 = 1.26mT

This would then suggest, for part ii), that the magnetisation for the iron alloy is (1.58 - 0.00126)T = 1.579T

It seems the iron alloy has been rather hugely magnetised by such a small applied field!
I worry if this is actually correct, or I've done something wrong..?

Thanks
 
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sa1988 said:
So I get B = 1.26E-6 * 5000 * 0.2 = 1.26mT

This would then suggest, for part ii), that the magnetisation for the iron alloy is (1.58 - 0.00126)T = 1.579T
Is this the value for M or for μ0M?

It seems the iron alloy has been rather hugely magnetised by such a small applied field!
Yes. Ferromagnetic materials are amazing! :smile:
 
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TSny said:
Is this the value for M or for μ0M?Yes. Ferromagnetic materials are amazing! :smile:

Ah, oops, yeah I missed out the μ0 term.

Still I was shocked by the seemingly huge resultant B field from such a tiny current in the solenoid.

So M = (B-Bapp)/μ0 = (1.58-0.00126)/μ0

However I'm now shocked again because this gives a magnetisation of 1.25E6... which is huge! (Or is it...?) I can't seem to find any examples online with actual numerical values for me to consider as a reference towards my own answer.

Simply, I don't know what a typical magnetisation value should look like. Should it be as huge as that?

Thanks :oldsmile:
 
Yes, your numbers look reasonable for iron. It is amazing and it shows what a large group of entities (atoms) can accomplish when they cooperate.
 
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TSny said:
Yes, your numbers look reasonable for iron. It is amazing and it shows what a large group of entities (atoms) can accomplish when they cooperate.

Great stuff, thanks :angel:
 

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