1. The problem statement, all variables and given/known data A physics student has two cubes of iron. One cube has three times the volume of the other. The cubes are heated over identical flames for the same amount of time. The cubes are then removed and the temperature of each cube is recorded immediately. How will the thermometer readings compare? 2. Relevant equations Q=mc∆t 3. The attempt at a solution My initial thought was that a smaller volume meant a smaller mass and that the smaller mass would have a lower temperature than that of the bigger volume. 1. The problem statement, all variables and given/known data A physics student has three cubes of metal: a 100 g cube of iron, a 300 g cube of iron, and a 100 g cube of aluminum. The student puts the cubes into a beaker of boiling water. The cubes remain in boiling water until each cube is as hot as it is going to get. The cubes are then removed and the temperature of each cube is immediately recorded. How will the thermometer readings compare? Which cube reached its final temperature most quickly? Discuss how the answers to this exercise differ from the answers to the preceding exercise. 2. Relevant equations Specific Heat of Aluminum: 0.215 cal/g/degree Celsius Specific Heat of Iron: 0.1 cal/g/degree Celsius Specific Heat of Water: 1 cal/g/degree Celsius Q=Q=mc∆t 3. The attempt at a solution 1. The 100 g iron cube would have the highest temperature because of its small mass. The 100 g aluminum cube would have the lowest temperature because of its high specific heat. 2. The 100 g iron cube would reach its final temperature first. 3. ???