Is Bernoulli's Theorem an Expression of Energy Density in Fluids?

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The discussion centers on the relationship between Bernoulli's theorem and energy density in fluids, particularly regarding pressure and internal energy. It is noted that pressure is not equivalent to internal energy density, and while pressure can be related to energy per unit volume, it does not strictly equal energy density. The conversation highlights that the factor of 2/3 in the context of ideal gases is specific and does not apply universally. Additionally, pressure is described as a measure of enthalpy per unit volume, which complicates its interpretation as energy density. Ultimately, the nature of pressure and its relation to energy density remains a nuanced topic requiring further exploration.
anuttarasammyak
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As summarized.
 
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I think the complete thermodynamic equation should be $$\left( \frac{\partial U}{\partial V} \right)_T = -P + T \left( \frac{\partial P}{\partial T} \right)_V$$i.e. ##P = - \frac{\partial U}{\partial V}## is a special case, not applicable here
 
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etotheipi said:
i.e. P=−∂U∂V is a special case, not applicable here
Thanks for your teaching.
Thermodynamics relation says
p=\frac{F-G}{V}\neq \frac{E}{V}
p is volume density of ##F-G##. I feel it too abstract.
 
anuttarasammyak said:
Summary:: Pressure and energy of of ideal gas are p=NkT/V, E=3/2 NkT. So p=2/3 E/V. Why it is not E/V because pressure is energy per volume? How do I reconcile this ?

As summarized.
It only works out that way for the special case of an ideal monoatomic gas.
 
As @Chestermiller noted, the 2/3 term comes from a specific case. Ultimately, I think the important thing here is that 2/3 carries no units. The fact that pressure has units of energy per unit volume implies that
p\propto \dfrac{E}{V},
but does not in any way require
p = \dfrac{E}{V}.
 
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Also, even in the ideal gas limit of low density, real gases do not have constant heat capacity down to absolute zero.
 
Thanks. I could confirm pressure is not internal energy density. Do we have a general interpretation what kind of energy density pressure has ?
 
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anuttarasammyak said:
Thanks. I could confirm pressure is not internal energy density. Do we have a general interpretation what kind of energy density pressure has ?
Who says it can be interpreted that way?
 
I find in Wiki Energy Density
"In short, pressure is a measure of the enthalpy per unit volume of a system."
I do not catch it. Is it helpful to understand pressure as kind of energy density ?

The article says as for magnetic field, pressure and energy density coincide. It appears so in Maxwell stress tensor.
 
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  • #10
That's a bit strange since enthalpy density is related to energy density and pressure by ##h=u+P##.
 
  • #11
Putting one of those equations above into plain words (my plain words, if you want to shoot them down, go ahead); a static force may be described as having an incipient potential to do work, subject to it bearing on a linear displacement, and therefore a force per unit area for a given incipient displacement is the same as an energy for a given incipient change of volume.

(that is, the 'incipient energy change' is the force x 'incipient displacement')

[For example, a force of 100kN bearing on a m^2 area, per meter of displacement that force applies, it does work at the rate of 100kJ, i.e. the same work density as 100kJ/m^3.]

This only covers the first component of the thermodynamic equation above, however, it does not describe the nature of the work done to form the pressure. It is only a partial description covering the work the pressure can do.
 
  • #12
Re: #3 and #10, can we say
p=\frac{H-E}{V}=\frac{G-F}{V}
pressure as difference of the two free energy density?

For an example may I interpret that RHS constant of Bernouill's theorem
\frac{1}{2}\rho v^2 + \rho g h + p = const.
has dimension of energy density but the value is enthalpy density (minus constant internal energy for incompressible fluids and plus kinetic and potential energy density ) ?
 
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