Is Calculating 69g's as 676.89 m/s² Correct?

Thread starter Oblivion77
Start date Nov 29, 2008
Tags

Acceleration

AI Thread Summary

Calculating an acceleration of 69g's as 676.89 m/s² is correct, as it involves multiplying 69 by the acceleration due to gravity (9.81 m/s²). This conversion is valid and reflects the same physical quantity in different units. While both forms convey the same information, the standard practice in physics is to express acceleration in m/s². Therefore, using 676.89 m/s² is appropriate for clarity in scientific contexts. The discussion emphasizes the importance of unit consistency in physics calculations.

Nov 29, 2008

Oblivion77

Homework Statement

If I had an acceleration of A=69g's can I just say A=69(9.81) = 676.89m/s^2?

Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Nov 29, 2008

Ichiro101

Depends on the context. You are essentially stating the same thing just in different words/numbers. In physics, we would prefer the form (m/s^2) however,.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »