Is gravity significant in this scenario?

AI Thread Summary
The discussion centers on calculating the time it takes for a 5.0 kg mass to reach a speed of 4000 m/s when accelerated by a net force of 490,000 N. The initial calculation suggests it takes approximately 0.041 seconds to achieve this speed. Participants debate the significance of gravity in this scenario, questioning whether it has been factored into the net force. It is concluded that since the acceleration occurs horizontally and the mass reaches the required speed before needing to consider orbital mechanics, gravity can be neglected for this calculation. Ultimately, the focus remains on whether the initial answer is correct without accounting for gravity.
Cheddar
Messages
38
Reaction score
0

Homework Statement


A large gun accelerates a 5.0 kg mass from rest to a speed of 4000 m/s into orbit. The net force accelerating the bullet is 490,000 N.
How long will it take the projectile to come up to speed?
It doesn't say anything above air resistance or gravity.

Homework Equations


acceleration = net force / mass
time = velocity / acceleration

The Attempt at a Solution


0.041 seconds (using the equations listed above)
What about gravity? Was this already calculated into the net force?
 
Physics news on Phys.org
Cheddar said:
A large gun accelerates a 5.0 kg mass from rest to a speed of 4000 m/s into orbit.

Hi Cheddar! :smile:

This question doesn't make any sense …

if the mass goes into orbit, the orbit obviously passes through the end of the gun …

in other words, if the gun is on Earth, then the mass crashes, and doesn't go into orbit. :confused:
 
I think I might have heard something along these lines. Does it have anything to do with this?

300px-Newton_Cannon.svg.png


Good ol' Newton

Perhaps when it says large, it really means large
 
Cheddar said:

The Attempt at a Solution


0.041 seconds (using the equations listed above)

Looks good, I think the problem is just this simple ... though tiny-tim is correct, since the gun is presumably on the surface of the Earth it will return to Earth after one single orbit (neglecting air resistance).

What about gravity? Was this already calculated into the net force?
A reasonable question. Try comparing the force of gravity to the 490,000 N force being applied.
 
Kaimyn said:
I think I might have heard something along these lines. Does it have anything to do with this? …

ah! thanks Kaimyn! … the ol' do-it-from-the-top-of-Mount-Everest trick! :biggrin:

in that case, Cheddar, you can forget about gravity …

the gun, and the acceleration, will be horizontal (and the mass will be supported by the bottom of the barrel of the gun :wink:).
 
Kaimyn said:
Perhaps when it says large, it really means large


The acceleration occurs over roughly 80 meters, very small compared to the size of the Earth.

But the orbit issue really is irrelevant here.
 
4000/(490000/5) What they're basically asking is how long will it take to reach 4000m/s.
 
Thank you everyone for your input.
Now, I realize that the fact that the mass is being projected into orbit doesn't matter.
Since the speed of the mass is going to reach 4000 m/s well before reaching orbit.
The question is whether my answer correct as it is (neglecting gravity) or should I be accounting for gravity at some point in the equations?
 
Cheddar said:
The question is whether my answer correct as it is (neglecting gravity) or should I be accounting for gravity at some point in the equations?

I repeat:

Redbelly98 said:
Try comparing the force of gravity to the 490,000 N force being applied.
 
Back
Top