IS IT POSSIBLE TO SOLVE FOR m2 from a(m1+m2) = (m2g-m1g)?

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AI Thread Summary
The discussion revolves around solving the equation a(m1+m2) = (m2g-m1g) for m2, where g represents gravity. Participants confirm that it is possible to isolate m2 if values for acceleration (a) and mass m1 are known. One user successfully derives the formula m2 = (m1a + m1g) / (g - a) after initially expressing it differently. The context is related to an Atwood machine problem, where one mass is known and the other needs to be determined using the given acceleration. The conversation emphasizes providing guidance without directly solving the homework for the original poster.
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Homework Statement



a=(m2g-m1g)
------------- divided by IS IT POSSIBLE TO SOLVE FOR m2 =?
(m1+m2) where g = gravity


Homework Equations



a(m1+m2) = (m2g-m1g)
where g = gravity

The Attempt at a Solution



a(m1+m2) = (m2g-m1g)

IS IT POSSIBLE TO SOLVE FOR m2 =? where g = gravity

THANKS!
 
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tigerwoods99 said:

Homework Statement



a=(m2g-m1g)
------------- divided by IS IT POSSIBLE TO SOLVE FOR m2 =?
(m1+m2) where g = gravity


Homework Equations



a(m1+m2) = (m2g-m1g)
where g = gravity

The Attempt at a Solution



a(m1+m2) = (m2g-m1g)

IS IT POSSIBLE TO SOLVE FOR m2 =? where g = gravity

THANKS!

You can certainly isolate it on one side of the equation to get m2 = ___________

Whether you can "solve" for it depends on if you have "a" and "m1" as knowns.
 
lol..

<< most of solution deleted by berkeman >>

This however looks completely ridiculous, what is it you are trying to solve??
 
Unto said:
lol..

<< most of solution deleted by berkeman >>

This however looks completely ridiculous, what is it you are trying to solve??

Please remember not to do the OP's homework for them. We can offer tutorial help, but do not work their equations for them. Thanks.
 
Thanks! i just solved it myself lol. i got m2 = (-m1a-m1g)/(a-g) but i guess i will multyply by -1/-1 to make it (m1a+m1g)/g-a

and I am trying to solve an atwood machine problem. For example, 1 mass is given and the other is not given, and you know the acceleration so m2 = blabla really helps!
 
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