Is It Possible to Solve This Vector Problem with Given Information?

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The discussion centers around a challenging vector problem involving three forces in a 3D plane, where the resultant force is given as "-2J + 5K." The magnitudes of two forces, F1 and F2, are provided, but there is confusion regarding the angles and the lack of information for F3. Participants express that the problem seems impossible to solve with the given data, particularly noting the absence of a scalar product or direction for F2. Despite the instructor labeling it as "easy," many students struggle to find a solution, leading to a consensus that the problem likely contains insufficient information. The conversation concludes with a shared sense of frustration and agreement on the inadequacy of the provided details.
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I just had a test Friday and I spent 30 minutes on this so-called "Easy" problem. The resultant force is "-2J + 5K" and there are 3 forces that compose this resultant force.

The Magnitude of F2 is 5kN
The Magnitude of F1 is 3kN
F1 has a angle of "0" to the Y axis


The 3 forces are all acting on a 3D vector plane, but no vector has a value for "I". So none are moving in the x direction.

Given the image below (Forgive the crude drawing):
Find:
The Magnitude of F3
The Angle that F3 is acting apon
And the Magnitude of the Resultant force.

Can this be done given the information in my drawing? I didn't leave anything off, this is what we were given and I even asked my instructor if we were missing information. I couldn't solve this one, and many in my class had problem just as I did. This is a second year college level course.

If you can help me out, thanks, I really would love any help I could get.



vectors.jpg
 
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Bymp said:
The Magnitude of F2 is 5kN
No angle given?
The Magnitude of F1 is 3kN
F1 has a angle of "0" to the X axis
I presume you mean 0 degrees to the y-axis.
 
Actually I didn't understand that part either, what he place on the test looked like a letter "O" for the angle, so it confused me. I persumed that I could solve the angle there by using the formula:

Cos Angle = (A *dot* B) / [(Magnitude of A) * (Magnitude of B)]

I believe that's a common vector reference. I believe I typed that correctly
 
I fixed that as well, the angle was 0 degrees to the x- axis, thank you
 
Bymp said:
Actually I didn't understand that part either, what he place on the test looked like a letter "O" for the angle, so it confused me. I persumed that I could solve the angle there by using the formula:

Cos Angle = (A *dot* B) / [(Magnitude of A) * (Magnitude of B)]
I don't understand. Are you given the scalar product of A and B? (Sure, if you're given the magnitude of two vectors and their dot product, you can get the angle between them. But are you given that information?)

Was the direction of F2 specified or just its magnitude?
 
Oh, true, I was mistaken, your right. I apoligize.

All information supplied in the image and the first post should be 100% correct now.

What is supplied what what was supplied.

I'm just trying to think of ways I could have solved this. He claimed this was an "Easy" problem requiring only 10 minutes of work at the most.

But you are right, we can't use that because we are not given the scalar product of the two.
 
I just can't find any way to solve for the wanted values =\

Sept the magnitude of the resultant force... that's the only way I could solve for.
 
Sure looks like insufficient information to me.
 
Thanks =) Just glad someone agrees with me, thank you very much, my mind is at better rest now
 
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