Is sin convergent or divergent

Click For Summary
SUMMARY

The discussion clarifies the convergence and divergence of the sine and cosine functions. It establishes that both sin(x) and cos(x) oscillate indefinitely, leading to the conclusion that their limits as x approaches infinity do not exist, thus categorizing them as divergent functions. The confusion arises from the application of convergence and divergence terminology, which is more relevant to sequences or series rather than individual functions. The conversation emphasizes the importance of understanding the context in which these terms are applied.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with oscillatory functions
  • Knowledge of improper integrals
  • Basic concepts of convergence and divergence in mathematical analysis
NEXT STEPS
  • Study the properties of oscillatory functions in calculus
  • Learn about limits and their applications in determining convergence
  • Explore improper integrals and their convergence criteria
  • Investigate the definitions of convergence and divergence in sequences and series
USEFUL FOR

Students studying calculus, particularly those working with limits and improper integrals, as well as educators seeking to clarify the concepts of convergence and divergence in mathematical functions.

trumpetplaya1687
Messages
2
Reaction score
0
I just have a quick question, is cos and sin divergent or convergent? I keep getting mixed results from different sources. I know that both functions oscillate so on the interval [0, infinity) they both diverge. But for some of my homework problems relating to improper integrals, the book says that both functions approach some number. I need some guidance as to when both functions approach a number and when they both are divergent. Please help.
 
Last edited:
Physics news on Phys.org
The words "convergence" and "divergence" simply do not apply to functions- they apply go sequences or series of numbers or functions.

I think you are trying to ask if [itex]lim_{x\rightarrow \infty} sin(x)[/itex] and [itex]lim_{x\rightarrow \infty} cos(x)[/itex] exist. You are correct that those limits do not exist.

Could you please post the exact example your text gives?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 16 ·
Replies
16
Views
2K