Is the Current Zero When a Capacitor is Fully Charged?

AI Thread Summary
The discussion centers on whether the current in a capacitor circuit is zero when the capacitor is fully charged. It clarifies that while a fully charged capacitor does not allow further current flow, at the moment the switch is closed, the capacitor still has a potential difference that allows current to flow through the resistor. The initial current is not zero because the capacitor discharges immediately upon closing the switch, creating a current path. The confusion arises from the assumption that an open switch implies zero current, which is incorrect in this context. Understanding Kirchhoff's loop rule helps clarify the current behavior in the circuit.
charlies1902
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I attached the problem. Is the answer they have for part b wrong? shouldn't the current be 0?
 

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I'd say it is right. The capacitor chargers to a value equal to the voltage of the source, E. Upon moving to position B, the capacitor discharges but you can assume that at t=0- the voltage across the capacitor is indeed E.This is the instantaneous current at t=0-, which degrades as t increases.
 
Yes and no.
At the level the problem is set (in terms of ideal components): no (the initial current should not be zero).
Initially in the RC circuit, the capacitor does not resist the flow of current so the current in the circuit is the same as through the resistor alone.

Perhaps you are thinking that since the switch is open at the start, then there must be zero current at the instant the switch is closed?
 
charlies1902 said:
I attached the problem. Is the answer they have for part b wrong? shouldn't the current be 0?

Nope. The current won't be zero. The capacitor has a charge on it, hence a potential difference. When the switch is closed on position b, that potential difference "sees" a path through the resistor. So current flows immediately.
 
ah I see I got my concept wrong. I thought that when a capacitor is fully charged, the current would be 0. I just did kirkoffs loop rule and got their answer. thanks.
 
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