Is the following a matrix? (yes/no)

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Homework Statement



Is the following a matrix?

Given: these identities (ordinarily in "Feynman slash notation": not sure how to do slashes in LaTeX):

\begin{array}{c}<br /> ({\gamma _\mu }{a^\mu }){\gamma _\nu }{b^\nu } + {\gamma _\nu }{b^\nu }({\gamma _\mu }{a^\mu }) \equiv 2{a_\mu }{b^\mu } \\ <br /> ({\gamma _\mu }{a^\mu })({\gamma _\mu }{a^\mu }) \equiv {a_\mu }{a^\mu } \\ <br /> \end{array}

Homework Equations



({\gamma ^\mu }{\partial _\mu })({\gamma ^\nu }{A_\nu }) + ({\gamma ^\nu }{A_\nu })({\gamma ^\mu }{\partial _\mu }) = ... a matrix or a vector?

The Attempt at a Solution



Maybe it is a matrix. My final answer needs a matrix answer (specifically: I need the field-strength tensor, F^{\mu, \nu}, to pop up eventually.

Maybe it isn't a matrix. The operator \partial _\mu is a differential operator, and A is the four-vector-potential. that suggests I should wind up with a differentiated version of the field-strenght tensor, which would be awfully-boring in a certain gauge I forget the name of (it'd be zero/divergenceless, a la Griffiths Intro Elementary Particles, p. 239-240).

?
 
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\partial_{mu} is a one-form. Contracting a one-form with a vector yields a scalar. In fact, all your terms are one-form vector contractions.
 
Phrak said:
\partial_{mu} is a one-form. Contracting a one-form with a vector yields a scalar. In fact, all your terms are one-form vector contractions.

Oh dear...back to the drawing board...
 
Phrak said:
\partial_{mu} is a one-form. Contracting a one-form with a vector yields a scalar. In fact, all your terms are one-form vector contractions.
But \gamma^\mu are the Dirac matrices, so the contraction \gamma^\mu A_\mu is actually a linear combination of matrices.

http://en.wikipedia.org/wiki/Gamma_matrices
 
In which case the contraction yields the same type as the Dirac matrix.
 
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