An antimuon and electron may bind together via Coulomb attraction and then decay, but is the following process possible? (µ+e-) → νe + νµ_bar
*The νµ_bar is the antiparticle of the muon neutrino - the antimuon neutrino
More than one answer (below) may be correct.
a) This decay mode can proceed naturally.
b) This decay would violate electron-lepton number. 0 + 1e → 1e + 0
c) This decay would violate muon-lepton number. -1μ + 0 → 0 - 1μ
d) This decay would violate tau-lepton number. 0 + 0 → 0 + 0
e) This decay would violate charge conservation. +1 - 1 → 0 + 0
Lepton numbers, charge, conservation
The Attempt at a Solution
(µ+e-) → νe + νµ_bar
µ+: lepton number: -1
e-: lepton number: +1
νe: lepton number: +1
νµ_bar: lepton number: -1
(-1µ++1e-) → +1νe + 1νµ_bar
electron-lepton number and muon-lepton number is conserved. There are no tau's in the equation. Therefore, b),c),d) are incorrect.
µ+ charge = +1
e- charge = -1
νe charge = 0
νµ_bar charge = 0
(+1µ+-1e-) → 0νe + 0νµ_bar
The net charge on both sides of the equation equals zero. Therefore, e) is incorrect.
So, by that logic I'd say the answer is a) This decay mode can proceed naturally.