Is the Set of 3x3 Matrices Annihilating a Given Vector a Subspace?

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Homework Statement


Are the 3X3 matrices A such that vector <1,2,3> is in the kernel of A, a subspace of R^(3X3)?

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The Attempt at a Solution


I know that the kernel condition gives a subset V={A|A*<1,2,3>=0} but I am not sure of how to proceed to show it is in fact a subspace. Should I try to see if it spans or use the definition of a subspace? I'm just confused on how to proceed with the next step
 
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To show that it's a subspace, you have to show that if it contains u and v, then it contains au + bv where a and b are scalars, that it contains 0 and that it contains -u for any u that it contains.
 
To expand slightly on what aPhilosopher said, let U and W be matrices in your subset V. It's sufficient to show that aU + bW is also in the same subset, for any scalars a and b.

Showing that the subset contains the zero matrix corresponds to a = b = 0. Showing that -U is in the subset corresponds to a = -1 and b = 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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