Is the Upper Optical Path Longer than the Lower One in Diagram 2?

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In the discussion about the optical paths in Diagram 2, it is established that the upper ray (S1P - t + ut) is longer than the lower ray (S2P) due to the refractive index (u) being greater than 1 for regular materials. This leads to the conclusion that the optical path of the upper ray exceeds that of the lower ray. The confusion arises from the calculation suggesting a negative thickness (mt t), which is incorrect. The relationship between the paths indicates that the upper ray's optical path is indeed longer. Understanding the impact of the refractive index is crucial in this analysis.
desmond iking
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for diagram 2 , i just can't understand why S1P -t + ut (upper ray ) is longer than the lower light ray (S2P) , ? if I take S2P minus ( S1P -t + ut ) , then i would get mt t (thickness ) is negative , which is indeed wrong! so it has shown that optical path of the upper ray is longer than the optical path of lower ray ...

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S1P - t + ut > S2P if u>1, as S2P=S1P based on the upper diagram. I guess u is your refractive index? Regular materials have a refractive index larger than 1, so the upper path is longer.
 
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